Boolean between different shapes rather than layers

Comments

• Matthias

  January 2018 edited January 2018

  Hi Hamed,

  The recommended approach is to use the Region class:

  shape = ... the input shape 1 ...
  shape2 = ... the input shape 2 ...
  region = RBA::Region::new(shape1.polygon)
  region2 = RBA::Region::new(shape2.polygon)
  region &= region2   # or whichever operation you plan
  

  The result of an AND operation can be zero, one or many polygons. Hence there is no
  "polygon & polygon -> polygon" operation. The region object accommodates zero to many
  polygons, so it's the natural representation for input and output to an AND operation.

  Matthias
• hpishvai

  January 2018 edited November -1

  Hi Matthias,
  
  Thank you so much for the hint.
  
  In order to test what you proposed, I am inserting a BOX into the layout:
  
  shape1 = lyo.layout.cell( @cell_index[@cell_name] ).shapes( call_layer( lyo, @layer_name,fab_name ) ).insert(RBA::Box::new(0, -50/0.001, 2000/0.001, 50/0.001))
  
  
  and then use:
  
  region = RBA::Region::new(shape1.to_polygon)
  
  for some reason I get an error "undefined method "to_polygon" for BOX(0,-50,100,50):RBA::Shape"
  
  Any idea what is causing the issue?
  
  Thank you,
  Haed
• Matthias

  January 2018 edited November -1

  Sorry, typo. Should be "shape1.polygon" (answer edited).

  Matthias
• hpishvai

  January 2018 edited January 2018

  Hi Matthias,
  
  Thank you so much for looking into this.
  
  I really do not understand why but this is not working for me
  
  shape1 = lyo.layout.cell( @cell_index[@cell_name] ).shapes( call_layer( lyo, @layer_name,fab_name ) ).insert(RBA::Box::new(0, 80/0.001, 20/0.001, 100/0.001))
  region = RBA::Region::new(shape1.polygon)
  
  shape2 = lyo.layout.cell( @cell_index[@cell_name] ).shapes( call_layer( lyo, @layer_name,fab_name ) ).insert(RBA::Box::new(0, 90/0.001, 30/0.001, 120/0.001))
  region2 = RBA::Region::new(shape2.polygon)
  
  region &= region2
• Matthias

  January 2018 edited January 2018

  How should I?

  I can't see what call_layer will do, neither what @cell_index really contains ... if it's an array or a hash at all.

  And I don't print error messages just for fun. Don't be shy and tell me what they say.
• hpishvai

  January 2018 edited November -1

  I totally understand Matthias. Sorry for sending you three lines of code. My program is quite long that's why I could not copy it here. If you do not mind I will attach it to an e-mail and send it to you.
  
  Regards,
  Hamed
• hpishvai

  February 2018 edited November -1

  Problem is solved now.