rounak1068
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@Matthias, In your Code also If I'm giving top cell name, then its working fine
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@Matthias, now I got the point, for clipping top-Cell name is mandatory otherwise tool is got confuse which cell you are selecting. here is my code that is working fine but kindly review once, that my approach is correct or not ? KLAYOUT = pya.Lay…
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That ruby code given by @Matthias, I tried in ruby environment. Same error I'm getting.
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@"Vincent Lin", I tried this also but I'm getting error (No overload with matching arguments in Layout.clip)
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here is my code but not working. import pya input_gds = "abc.gds" KLAYOUT = pya.Layout() KLAYOUT.read(input_gds) top_cell = KLAYOUT.top_cell() clip_rect = pya.DBox(50.0, 50.0, 100, 100.0) clip_cell = KLAYOUT.create_cell("CLIP&quo…
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@Matthias , kindly look into it. I got error while run above code.
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In above script I got error (No overload with matching arguments in Layout.clip)
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@EugeneZelenko, @"Vincent Lin" kindly look into that.
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import pya KLAYOUT = pya.Layout() gds_files = ["xyz.gds"] for each_gds in gds_files: KLAYOUT.read(each_gds) top_cell = None max_area = 0 for cell in KLAYOUT.each_cell(): bbox = cell.bbox() area = bbox.widt…
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In above script the name of top-cell is hardcoded (top_cell_read.name != "xyz.gds":), but I want to find top- level cell from GDS via script then change the top-cell name.
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@"Vincent Lin" kindly provide suggestion for same.
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Great! Thank you for help! @"Vincent Lin"