Unable to load the library cells using library_by_name

Comments

• Matthias

  April 4

  Hi @Niharika04,

  I assume your library is bound to a technology. When you use "library_by_name" without "for_technology", you will not see these libraries. "library_by_name" applies the name and technology filter. Omitting "for_technology" does not mean "ignore technology attribute", but means "give me libraries not bound to a technology".

  So either specify a technology for iterate over libraries using a look like this:

  for id in pya.Library.library_ids():
    lib = pya.Library.library_by_id(id)
    if lib.name() == name:
      ...
  

  or

  [ pya.Library.library_by_id(id) for id in pya.Library.library_ids() if pya.Library.library_by_id(id).name() == name ]
  

  Matthias
• Niharika04

  April 9

  Hi Matthias, Thank you for getting back to me.
  I appreciate your response, it helped me fix the issue in my script.
  Regards,
  Niharika