"path" in ROUND_PATH, via script, not in dbu; DPath to Path, DPoint to Point

edited November 2015 in General

Hello,

My question arose in the context of the path returned from ROUND_PATH, which seems to be in microns, rather than database units like all the other objects...

iter = cell.begin_shapes_rec(layer)
while not(iter.at_end()):
if iter.shape().is_polygon():
  if iter.cell().basic_name() == "ROUND_PATH":
    subcell = iter.cell()        
    trans = iter.trans() # CplxTrans object of the instance 
    itrans = iter.itrans() # ICplxTrans object of the instance, integer version
    print "trans: %s, itrans: %s" % (trans, itrans)
    # apply itrans on path
    DPath = subcell.pcell_parameters_by_name()["path"]  # DPath object
    ipath = pya.Path.from_dpath(DPath)  # Construct an integer-coordinate path from a floating-point coordinate one
    print "%s: In cell {%s}, DPath -- %s -- Path -- %s"   % (i, iter.cell().name, DPath, ipath)

The above returns a path in microns, e.g., (0,0;10,0;10,10), rather than dbu, e.g., (0,0;10000,0;10000,10000)

....

Originally, I thought I could use the built-in functions to convert from dbu to microns.

I think I understand now that what I have below doesn't accomplish this -- namely this conversion is just a datatype conversion:

I am trying to convert from coordinates in database units (integer) to floating point in user units (microns). My understanding is that the path and points defined below, where I have 10 microns, it should be converted to 10000. But that's not the case. It just gets rounded.

Do I need to going through point by point and multiply by 1000 myself?

The documentation states: All floating-point type objects have class methods like "from_i.." (i.e. DBox#from_ibox) which convert integer-coordinate type objects to floating-point type ones without loss of precision. The reverse path is opened by using the "from_d.." class methods of the integer-type objects (i.e. Box#from_dbox). These methods however require some rounding and are therefore responsible for a potential distortion of the geometry of the object.

import pya

# http://www.klayout.de/doc/programming/geometry_api.html#h2-339
ly = pya.Application.instance().main_window().current_view().active_cellview().layout() 
dbu =  ly.dbu
print dbu

dpoints = [ [0,0], [10.01,0], [10.01,10] ]
dpoints=n.array(dpoints)/dbu
a1 = []
for p in dpoints:
   a1.append (pya.DPoint(p[0], p[1]))
dpath = pya.DPath(a1, 0.5/dbu)
ipath = pya.Path.from_dpath(dpath)  # Construct an integer-coordinate path from a floating-point coordinate one

print "dpath -- %s -- ipath -- %s"   % (dpath, ipath)


dpoint = pya.DPoint(10.333/dbu, 23.4/dbu)
# http://klayout.de/doc/code/class_Point.html
ipoint = pya.Point.from_dpoint(dpoint)  # Create a double point from an integer point (???)

print "dpoint -- %s -- ipoint -- %s"   % (dpoint, ipoint)

and the output

0.001
dpath -- (0,0;10010,0;10010,10000) w=500 bx=0 ex=0 r=false -- ipath -- (0,0;10010,0;10010,10000) w=500 bx=0 ex=0 r=false
dpoint -- 10333,23400 -- ipoint -- 10333,23400

Comments

  • edited November -1

    It seems like I can just scale the values returned by the PCell "ROUND_PATH"

        DPath = subcell.pcell_parameters_by_name()["path"]*(1/dbu)  # DPath object
    

    and get it back to dbu rather than microns...

  • edited November -1

    Hi Lukas,

    Oh yes ... maybe I forgot to mention this. The Path object is supposed to be micron units rather than database units.

    To convert an integer-typed path to a DPath in database units, you can also use the transformation, which will convert the type to DPath at the same time (the plain multiplication doesn't):

    dpath = ipath.transformed(RBA::CplxTrans.new(dbu))
    

    The PCell's parameters are supposed to be independent from the database unit. For example the circle radius is given in micron units, not in database units. The reason is that the PCell code is not necessarily executed in a context with the same database unit than the target layout. The PCell lives in a separate library which comes with it's own database unit. So having micrometer units ensures that the PCell physically looks the same in the library and in the target layout.

    Best regards,

    Matthias

  • edited November -1

    Good point. It makes sense to use microns for PCells.

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